Optimal. Leaf size=221 \[ -\frac{5 A+3 i B}{64 a^2 c^4 f (-\tan (e+f x)+i)}+\frac{5 A+i B}{32 a^2 c^4 f (\tan (e+f x)+i)}-\frac{-B+i A}{64 a^2 c^4 f (-\tan (e+f x)+i)^2}-\frac{3 A-i B}{48 a^2 c^4 f (\tan (e+f x)+i)^3}-\frac{B+i A}{32 a^2 c^4 f (\tan (e+f x)+i)^4}+\frac{5 x (3 A+i B)}{64 a^2 c^4}+\frac{3 i A}{32 a^2 c^4 f (\tan (e+f x)+i)^2} \]
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Rubi [A] time = 0.26789, antiderivative size = 221, normalized size of antiderivative = 1., number of steps used = 4, number of rules used = 3, integrand size = 41, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.073, Rules used = {3588, 77, 203} \[ -\frac{5 A+3 i B}{64 a^2 c^4 f (-\tan (e+f x)+i)}+\frac{5 A+i B}{32 a^2 c^4 f (\tan (e+f x)+i)}-\frac{-B+i A}{64 a^2 c^4 f (-\tan (e+f x)+i)^2}-\frac{3 A-i B}{48 a^2 c^4 f (\tan (e+f x)+i)^3}-\frac{B+i A}{32 a^2 c^4 f (\tan (e+f x)+i)^4}+\frac{5 x (3 A+i B)}{64 a^2 c^4}+\frac{3 i A}{32 a^2 c^4 f (\tan (e+f x)+i)^2} \]
Antiderivative was successfully verified.
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Rule 3588
Rule 77
Rule 203
Rubi steps
\begin{align*} \int \frac{A+B \tan (e+f x)}{(a+i a \tan (e+f x))^2 (c-i c \tan (e+f x))^4} \, dx &=\frac{(a c) \operatorname{Subst}\left (\int \frac{A+B x}{(a+i a x)^3 (c-i c x)^5} \, dx,x,\tan (e+f x)\right )}{f}\\ &=\frac{(a c) \operatorname{Subst}\left (\int \left (\frac{i (A+i B)}{32 a^3 c^5 (-i+x)^3}+\frac{-5 A-3 i B}{64 a^3 c^5 (-i+x)^2}+\frac{i A+B}{8 a^3 c^5 (i+x)^5}+\frac{3 A-i B}{16 a^3 c^5 (i+x)^4}-\frac{3 i A}{16 a^3 c^5 (i+x)^3}+\frac{-5 A-i B}{32 a^3 c^5 (i+x)^2}+\frac{5 (3 A+i B)}{64 a^3 c^5 \left (1+x^2\right )}\right ) \, dx,x,\tan (e+f x)\right )}{f}\\ &=-\frac{i A-B}{64 a^2 c^4 f (i-\tan (e+f x))^2}-\frac{5 A+3 i B}{64 a^2 c^4 f (i-\tan (e+f x))}-\frac{i A+B}{32 a^2 c^4 f (i+\tan (e+f x))^4}-\frac{3 A-i B}{48 a^2 c^4 f (i+\tan (e+f x))^3}+\frac{3 i A}{32 a^2 c^4 f (i+\tan (e+f x))^2}+\frac{5 A+i B}{32 a^2 c^4 f (i+\tan (e+f x))}+\frac{(5 (3 A+i B)) \operatorname{Subst}\left (\int \frac{1}{1+x^2} \, dx,x,\tan (e+f x)\right )}{64 a^2 c^4 f}\\ &=\frac{5 (3 A+i B) x}{64 a^2 c^4}-\frac{i A-B}{64 a^2 c^4 f (i-\tan (e+f x))^2}-\frac{5 A+3 i B}{64 a^2 c^4 f (i-\tan (e+f x))}-\frac{i A+B}{32 a^2 c^4 f (i+\tan (e+f x))^4}-\frac{3 A-i B}{48 a^2 c^4 f (i+\tan (e+f x))^3}+\frac{3 i A}{32 a^2 c^4 f (i+\tan (e+f x))^2}+\frac{5 A+i B}{32 a^2 c^4 f (i+\tan (e+f x))}\\ \end{align*}
Mathematica [A] time = 2.57616, size = 232, normalized size = 1.05 \[ \frac{\sec ^2(e+f x) (\sin (4 (e+f x))-i \cos (4 (e+f x))) (30 (A (-3-12 i f x)+B (4 f x+i)) \cos (2 (e+f x))+16 (3 A+4 i B) \cos (4 (e+f x))-360 A f x \sin (2 (e+f x))-90 i A \sin (2 (e+f x))-96 i A \sin (4 (e+f x))-9 i A \sin (6 (e+f x))+3 A \cos (6 (e+f x))-240 A-30 B \sin (2 (e+f x))-120 i B f x \sin (2 (e+f x))+32 B \sin (4 (e+f x))+3 B \sin (6 (e+f x))+9 i B \cos (6 (e+f x)))}{1536 a^2 c^4 f (\tan (e+f x)-i)^2} \]
Antiderivative was successfully verified.
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Maple [A] time = 0.073, size = 351, normalized size = 1.6 \begin{align*}{\frac{5\,A}{64\,f{a}^{2}{c}^{4} \left ( \tan \left ( fx+e \right ) -i \right ) }}+{\frac{{\frac{3\,i}{64}}B}{f{a}^{2}{c}^{4} \left ( \tan \left ( fx+e \right ) -i \right ) }}-{\frac{{\frac{i}{64}}A}{f{a}^{2}{c}^{4} \left ( \tan \left ( fx+e \right ) -i \right ) ^{2}}}+{\frac{B}{64\,f{a}^{2}{c}^{4} \left ( \tan \left ( fx+e \right ) -i \right ) ^{2}}}+{\frac{5\,\ln \left ( \tan \left ( fx+e \right ) -i \right ) B}{128\,f{a}^{2}{c}^{4}}}-{\frac{{\frac{15\,i}{128}}\ln \left ( \tan \left ( fx+e \right ) -i \right ) A}{f{a}^{2}{c}^{4}}}-{\frac{{\frac{i}{32}}A}{f{a}^{2}{c}^{4} \left ( \tan \left ( fx+e \right ) +i \right ) ^{4}}}-{\frac{B}{32\,f{a}^{2}{c}^{4} \left ( \tan \left ( fx+e \right ) +i \right ) ^{4}}}+{\frac{5\,A}{32\,f{a}^{2}{c}^{4} \left ( \tan \left ( fx+e \right ) +i \right ) }}+{\frac{{\frac{i}{32}}B}{f{a}^{2}{c}^{4} \left ( \tan \left ( fx+e \right ) +i \right ) }}-{\frac{5\,\ln \left ( \tan \left ( fx+e \right ) +i \right ) B}{128\,f{a}^{2}{c}^{4}}}+{\frac{{\frac{15\,i}{128}}\ln \left ( \tan \left ( fx+e \right ) +i \right ) A}{f{a}^{2}{c}^{4}}}-{\frac{A}{16\,f{a}^{2}{c}^{4} \left ( \tan \left ( fx+e \right ) +i \right ) ^{3}}}+{\frac{{\frac{i}{48}}B}{f{a}^{2}{c}^{4} \left ( \tan \left ( fx+e \right ) +i \right ) ^{3}}}+{\frac{{\frac{3\,i}{32}}A}{f{a}^{2}{c}^{4} \left ( \tan \left ( fx+e \right ) +i \right ) ^{2}}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F(-2)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Exception raised: RuntimeError} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [A] time = 1.08907, size = 383, normalized size = 1.73 \begin{align*} \frac{{\left (120 \,{\left (3 \, A + i \, B\right )} f x e^{\left (4 i \, f x + 4 i \, e\right )} +{\left (-3 i \, A - 3 \, B\right )} e^{\left (12 i \, f x + 12 i \, e\right )} +{\left (-24 i \, A - 16 \, B\right )} e^{\left (10 i \, f x + 10 i \, e\right )} +{\left (-90 i \, A - 30 \, B\right )} e^{\left (8 i \, f x + 8 i \, e\right )} - 240 i \, A e^{\left (6 i \, f x + 6 i \, e\right )} +{\left (72 i \, A - 48 \, B\right )} e^{\left (2 i \, f x + 2 i \, e\right )} + 6 i \, A - 6 \, B\right )} e^{\left (-4 i \, f x - 4 i \, e\right )}}{1536 \, a^{2} c^{4} f} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [A] time = 5.56188, size = 500, normalized size = 2.26 \begin{align*} \begin{cases} \frac{\left (- 2061584302080 i A a^{10} c^{20} f^{5} e^{8 i e} e^{2 i f x} + \left (51539607552 i A a^{10} c^{20} f^{5} e^{2 i e} - 51539607552 B a^{10} c^{20} f^{5} e^{2 i e}\right ) e^{- 4 i f x} + \left (618475290624 i A a^{10} c^{20} f^{5} e^{4 i e} - 412316860416 B a^{10} c^{20} f^{5} e^{4 i e}\right ) e^{- 2 i f x} + \left (- 773094113280 i A a^{10} c^{20} f^{5} e^{10 i e} - 257698037760 B a^{10} c^{20} f^{5} e^{10 i e}\right ) e^{4 i f x} + \left (- 206158430208 i A a^{10} c^{20} f^{5} e^{12 i e} - 137438953472 B a^{10} c^{20} f^{5} e^{12 i e}\right ) e^{6 i f x} + \left (- 25769803776 i A a^{10} c^{20} f^{5} e^{14 i e} - 25769803776 B a^{10} c^{20} f^{5} e^{14 i e}\right ) e^{8 i f x}\right ) e^{- 6 i e}}{13194139533312 a^{12} c^{24} f^{6}} & \text{for}\: 13194139533312 a^{12} c^{24} f^{6} e^{6 i e} \neq 0 \\x \left (- \frac{15 A + 5 i B}{64 a^{2} c^{4}} + \frac{\left (A e^{12 i e} + 6 A e^{10 i e} + 15 A e^{8 i e} + 20 A e^{6 i e} + 15 A e^{4 i e} + 6 A e^{2 i e} + A - i B e^{12 i e} - 4 i B e^{10 i e} - 5 i B e^{8 i e} + 5 i B e^{4 i e} + 4 i B e^{2 i e} + i B\right ) e^{- 4 i e}}{64 a^{2} c^{4}}\right ) & \text{otherwise} \end{cases} + \frac{x \left (15 A + 5 i B\right )}{64 a^{2} c^{4}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [A] time = 1.23693, size = 328, normalized size = 1.48 \begin{align*} \frac{\frac{12 \,{\left (15 i \, A - 5 \, B\right )} \log \left (\tan \left (f x + e\right ) + i\right )}{a^{2} c^{4}} + \frac{12 \,{\left (-15 i \, A + 5 \, B\right )} \log \left (\tan \left (f x + e\right ) - i\right )}{a^{2} c^{4}} - \frac{6 \,{\left (-45 i \, A \tan \left (f x + e\right )^{2} + 15 \, B \tan \left (f x + e\right )^{2} - 110 \, A \tan \left (f x + e\right ) - 42 i \, B \tan \left (f x + e\right ) + 69 i \, A - 31 \, B\right )}}{a^{2} c^{4}{\left (\tan \left (f x + e\right ) - i\right )}^{2}} + \frac{-375 i \, A \tan \left (f x + e\right )^{4} + 125 \, B \tan \left (f x + e\right )^{4} + 1740 \, A \tan \left (f x + e\right )^{3} + 548 i \, B \tan \left (f x + e\right )^{3} + 3114 i \, A \tan \left (f x + e\right )^{2} - 894 \, B \tan \left (f x + e\right )^{2} - 2604 \, A \tan \left (f x + e\right ) - 612 i \, B \tan \left (f x + e\right ) - 903 i \, A + 93 \, B}{a^{2} c^{4}{\left (\tan \left (f x + e\right ) + i\right )}^{4}}}{1536 \, f} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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